math
posted by bob .
1. 4x^213x=12
I need to solve this problem by factoring or using the quadtratic formula. I am stuck when using the quadtratic formula method. Please advise how to do this.
2. 5x^2+42=0
How many roots exist in this equation and what type are they?

1. 4x^213x 12 = 0
Playing around a bit with the pairs 4&3 and 6&2 as the constants, I get
(4x + 3)(x 4) = 0
That makes the roots x=3/4 and 4
2. x^2 = 42/5
There are two imaginary roots that have an "i" (sqrt(1) factor