# physics

posted by .

A particle moves with constant speed of 3m/sec along path y=3x^2
What is the acceleration of the particle at x=1.5m?

• physics -

Since the speed is constant, the acceleration must be caused by the change in direction. The angle of the trajectory to the x axis is
theta = arctan (dy/dx) = arctan (6x)
When x = 1.5, theta = arctan 9 = 83.66 degrees
The acceleration will be
(speed)x d(theta)/dt
= (speed)* d(theta)/dx* dx/dt

Take it from there.

## Similar Questions

1. ### math

Which three options are true about motion in a straight line. A. A particle which moves at an increasing velocity has a constant acceleration. B. If two particles always have the same velocity as each other, their separation does not …
2. ### math

A particle moves with constant speed of 3m/sec along path y=3x^2 What is the acceleration of the particle at x=1.5m?
3. ### Physics

In the figure, particle A moves along the line y = 26 m with a constant velocity of magnitude 2.6 m/s and parallel to the x axis. At the instant particle A passes the y axis, particle B leaves the origin with zero initial speed and …
4. ### physics help

The magnitude of the velocity of a particle which starts from rest 2 ft below the origin when t = 0 and moves along a vertical axis is directly proportional to the time after starting. The displacement of the particle during the time …
5. ### physics help

The magnitude of the velocity of a particle which starts from rest 2 ft below the origin when t = 0 and moves along a vertical axis is directly proportional to the time after starting. The displacement of the particle during the time …
6. ### calculus

a particle moves along a number line measured in cm so that its position at time t sec is given by s=72/(t+2) +k, k is a constant and t>=0 seconds. (a) Find the instantaneous velocity of the particle at t=4 seconds (b) Find the …
7. ### Physics

A particle moves along a circular path over a horizontal xy coordinate system, at constant speed. At time t1 = 4.80 s, it is at point (4.40 m, 6.20 m) with velocity (3.70 m/s) and acceleration in the positive x direction. At time t2 …
8. ### PHYSICS1

A particle moves along a circular path over a horizontal xy coordinate system, at constant speed. At time t1 = 4.90 s, it is at point (5.30 m, 5.30 m) with velocity (2.20 m/s) and acceleration in the positive x direction. At time t2 …
9. ### physics

A particle moves along a circular path over a horizontal xy coordinate system, at constant speed. At time t1 = 4.60 s, it is at point (4.30 m, 6.20 m) with velocity (3.30 m/s) and acceleration in the positive x direction. At time t2 …
10. ### Physics

A 0.500 kg particle moves in a circle of R=0.0150 m at constant speed. The time for 20 complete revolutions is 31.7 s. What is the period T of the motion?

More Similar Questions