Algebra
posted by kaylee .
My homework is to solve by completing the square. But how can you complete the square on this problem?
3x^2 + 7x  8
The 3 doesn't factor out.

Is the expression you just wrote supposed to be equal to zero? You cannot solve for x unless you write an equation.
Write it as 3[x^2  (7/3)x + 8/3]= 0
This implies [x^2  (7/3)x + 8/3]= 0
For a perfect square within the brackets, you'd want to rewrite it as
[x(7/6)]^2 + 8/3  49/36
= [x(7/6)]^2 + 47/36 = 0
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