Logs-Algebra

posted by .

How do you graph the following logs?

f(x)=log5 (x-2)
f(x)=log5 x-2
f(x)= log5 x
f(x)=log5 (x+2)

  • Logs-Algebra -

    use f(x)= log5 x as your reference graph.

    You should know what your standard log function graph looks like

    If you translate the reference graph 2 units to the right, you get the first equation
    If you translate the reference graph 2 units to the left, you get the last equation

    If you translate the reference graph 2 units downwards, you get the second equation

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. check!

    here is the question: log5(x-4)= log7x solve for x. These are just base 10 logs. log100 = 2 This equation has the same format as log 40 = log (2x20) Since both sides have log base 10, you divide by log base 10 and end up with 5(x-4) …
  2. Algebra II

    Use log5(2)=0.4307 and log5(3)=0.6826 to approximate the value of log5=54. According to the example in my book I would divide 0.6826 by 0.4307 and the answer is 1.5848 but this is not one of the answers given. My choices are: a) 0.1370 …
  3. Algebra II

    Log6(6^9)=??? Answer: 9 Ine^-3x=??? Answer: -3x Use log5(2) = 0.4307 and log5(3) = 0.6826 to approximate the value of log5(12) Answer: log5(2) + log5(3)=log5(2^2*3) 2(0.4307) + 0.6826=1.544 so approximate value of log5(12)=1.544 I
  4. Algebra

    How come log5 25^4 reduces to 4 log5 25 then 4 times 2 then finally eight?
  5. Algebra 2

    Express as a logarithm of a single number or expression: 1. 5log4^p+log4^q 2. log10^x-4 log10^y 3. 4log3^A-1/2 log3^B 4. log5^M+1/4 log5^N 5. log2^M+log2^N+3 6. log5^x-log5^y+2 7. 1-3 log5^x 8. (1+log9^x)/2 I need to see all of the …
  6. precalculus

    solve the logarithmic equation . express solution in exact form log5(x-9)+log5(x+4)=1+log5(x-5)
  7. college algebra

    solve the logarithmic equation. Please show all work. log5x+log5(x-3)=log5(x+5)
  8. mathematics

    Given that log5 3=0.683 and log5 7=1.209.without using calculator,evaluate (a) log5 1.4 b)log7 75 c) log3 125
  9. Logarithm help

    using logarithms to solve exponential equations. 5^1+x = 2^1-x I need exact numbers. I did one on my own already. 5^x-1 = 9 5^x-1 = 9 log(5^x-1) = log9 (log5)(x-1) = log9 x-1 = (log9/log5) x= (log9/log5)-1 x = 2.3652
  10. Algebra 2

    Can someone help me solve this problem please?

More Similar Questions