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Chemistry

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Calculate the enthalpy change when 100. g of ice at 0.0 °C is heated to liquid water at 50.0°C. (The heat of fusion for water is 333 J/g.)

1)54.2 kJ
2)33.3 kJ
3)54,220 kJ
4)20.9 kJ

  • Chemistry -

    1)54.2 kJ
    2)33.3 kJ
    3)54,220 kJ
    4)20.9 kJ

    Those are possible answers... Which is it?

  • Chemistry -

    q1 = heat to melt the ice.
    q1 = mass of ice x heat of fusion.

    q2 = heat to raise the temperature from 0 degrees C to 50 degrees C.
    q2 = mass of water x specific heat water x (Tf - Ti)
    Tf is final Temperature.
    Ti is initial T.
    Total heat = q1 + q2.
    Post your work if you get stuck.

  • Chemistry -

    Never mind, I got it:

    100 grams of ice times 333 J/g = 33.3 kJ of heat to melt all the ice.

    Next, raising temperature of liquid, so 100 g *4.184 J/g *50= 20.92 kJ

    Thus A is best answer

  • Chemistry -

    right. In fact, I obtained 54.2 kJ.

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