posted by Jen .
Could you help me with the following problem, I don't understand how to do it.
Find an nth degree polynomial function with real coefficients satisfying the given conditions.
1. n=3; 3 and i are zeros; f(2)=20
f(x) = (x-3)(x-1)(x-a)
That function must be zero when x = 1 or 3.
Select the constant a so that f(2) = 20
(-1)(1)(2-a) = 20
a-2 = 20
a = 22