posted by Anonymous .
A 40 kg crate is pulled across the ice with a rope. A force of 90 N is applied at an angle of 36 degreees with the horizontal. Neglecting friction, calculate: the acceleration of the crate; the upward force the ice exerts on the crate as it is pulled
It might help to sketch a picture. The rope is at an angle of 36 degrees. It is usually important to know the x and y (horizontal and vertical) vectors from the 36 degree force in the rope. The x (horizontal) component is parallel to the ice and the old faithful f=ma can be used to find the acceleration. If there was no force in the rope, the ice would be pushing on the crate with the crate's weight. The vertical force in the rope must be added to the force due to gravity to find the total vertical (ice pushing) force. Be very careful with signs (directions) of the force when adding them.
can you give me answer
a 65 kg male skater pushes a 45 kg female skater causing her to accelerate at a rate of 2.0 ms ^2 at what rate will the male skater accelerate? What is the rate of his acceleration?