Honoirs Algebra
posted by Eddie .
Hello  I am afreshman & honors algebra is kicking my butt 
I need to simplify the following
(6c)(23c) can some on help

Use the FOIL method to expand it out. Google search it; it might help.
(6c)(23c) becomes:
12c + 18c^2
From here, you can factor it out or whatever it requires. 
Thanks so much

Multiply 6c by everything in the parentheses to clear the parentheses.
(6c*2) (3c*6c) =
12c + 18c^2 or
18c^2  12c but I don't that this equation is simpler.
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