Intermediate Algebra

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Combine like terms:
-3x^2+2x-4x^2-9+6x-2x^2+8


Solve for x:
8x-11= -11x+18


Solve for x:
-2(x-5)+7=z-8-5x


Solve for x:
(x-2)/5 - 3/2= (x+1)/10


Translate to an algebra statement; do not solve:
Seven times the difference of six and a twice a number yields the same result as the same number decreased by one.

  • Intermediate Algebra -

    I will be happy to critique your work. To solve for x, combine the terms that include x on one side and the constants on the other.

    "Combining" like terms" means separately combining the terms with different powers of x, and the constants.

  • Intermediate Algebra -

    Seven times the difference of six and a twice a number yields the same result as the same number decreased by one.

    How does this translate into a algebra statement?

  • Intermediate Algebra -

    7(6-x2) = x2-1

  • Intermediate Algebra -

    I can answer 3x^2+2x-4x^2-9+6x-2x^2+8

    first you want to combined all the squared problems whch is : 3x^2 -4x^2-2x^2
    Since two negatives make a positive : 3x^2-4x^2 =7x^2
    now subtract -2x^2 and that leaves for 5x^2

    Now you combine all the numbers with variables : 2x +6x = 8x
    so now we have
    5x^2+ 8x

    now we combine all the constant numbers -9+8= -1

    answer 5x^2+8x -1

  • Intermediate Algebra -

    Seven times the difference of six and a twice a number yields the same result as the same number decreased by one.

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  • Intermediate Algebra -

    The ratio of 7 more than a number to 2 less than that number is 13/4. Find the number

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