Can someone explain this question to me? I don't understand it. Show how to find the quotient 18 divided by (-6) by using A. The ideas of division as finding a missing factor. B. The procedures for integer division. Thanks.
Factor find the zeros x^5-9x^3 Find the quotient and remainder using long division (x^3-x^2-2x+6)/(x-2) Use sythetic division and remainder therem to evalulate P(c) Let P(x)= 6x^7-40x^6+16x^5-200x^4-60x^3-69x^2+13x-… *Calculate P(7) …
How do i do this using long division? This is part of a Partial Fractions Question. Please help, thanks! (x^3) / (x^3 - 2x^2 + 3x - 18) I tried using long division, but I could only get a quotient of 1, and a remainder of 2x^2 - 3x
Use synthetic division to find the quotient and remainder: (2x^5-7x^3-5x^2+1)/(x-2) This is what I got: Quotient: 2x^4+4x^3+x^2-3x-6 Remainder: -11 Do i just leave the quotient like this: 2x^4+4x^3+x^2-3x-6?
The annual budget projection for a large manufacturing firm includes: Division A $24,345,500 Division B $13,927,750 Division C $752,000 Division D $695,800 Estimate the total budget in millions of dollars.
how do you rewrite the problem so the divisor is a whole number 48.4 (division sign)0.4 8.19 (division sign)0.09 3.7 (division sign) 2.1 2.39 (division sign) 0.05 45.218(division sign)0.23 233.58(division sign)10.2