Michael Jordan's vertical leap is approximately 48in(1.2m). Keeping in mind gravitational acceleration of 9.8m/s2. What is his leap time?
The time spend going up equals the time spend coming down. The time to come down from height H is given by
H = (1/2) g t^2
Solve for t and double it
To calculate Michael Jordan's leap time, we need to use the equation of motion for vertical displacement in order to find how long it takes him to reach his maximum height:
Δy = V₀y * t + (1/2) *a * t²
In this equation:
- Δy represents the vertical displacement (1.2m).
- V₀y is the initial vertical velocity, which is 0 since Michael Jordan starts from rest.
- a is the acceleration due to gravity (-9.8m/s²).
- t is the time it takes for Michael Jordan to reach his maximum height.
Rearranging the equation, we get:
Δy = (1/2) * a * t²
Substituting the given values, we have:
1.2 = (1/2) * (-9.8) * t²
Simplifying further:
1.2 = -4.9 * t²
Dividing both sides by -4.9:
t² = -1.2 / -4.9
t² ≈ 0.2449
Taking the square root of both sides, we find:
t ≈ √0.2449
t ≈ 0.4949 seconds
Therefore, Michael Jordan's leap time is approximately 0.4949 seconds.