# chemistry

posted by .

how would you make a 4% percent paraformaldehyde solution?

Work:
starting from 20% (diluted with PBS)
V1C1=V2C2
(100)(20)=(x)(4)
x=500
496 ml of PBS (accounting for 4% paraformaldehyde) or would you add 500ml of PBS

Thank you

## Similar Questions

1. ### chemistry

Too make a 4% solution of paraformaldehyde from a 20 % solution. C1V1=C2V2 (20)(10ml)= (4)(x) x= 50ml so I would need to add 45ml of PBS and 4ml of the paraformaldhyde. Is that right.

how would you make a 4% percent paraformaldehyde solution?
3. ### chem

how would you make a 4% percent paraformaldehyde solution?
4. ### chemistry

the molar solubility of PbS, in a 0.150 M ammonium sulfide (NH4)2S solution is?
5. ### chemistry

Which of the species KClO2, NH4Br, HNO2, PbS is/are insoluble in water?
6. ### Chemistry

HELP!!! At temperatures above 930 ∘C, PbO reduces PbS to form metallic lead (Pb). The byproduct of the reaction is SO2. Calculate the amount of lead produced (in kg) when a reactor is charged with 487.0 kg of PbS and 750 kg of …
7. ### chemistry

At temperatures above 930 ∘C, PbO reduces PbS to form metallic lead (Pb). The byproduct of the reaction is SO2. Calculate the amount of lead produced (in kg) when a reactor is charged with 593.0 kg of PbS and 890 kg of PbO.
8. ### chemistry

At temperatures above 930 ∘C, PbO reduces PbS to form metallic lead (Pb). The byproduct of the reaction is SO2. Calculate the amount of lead produced (in kg) when a reactor is charged with 887.0 kg of PbS and 1330 kg of PbO.
9. ### chemistry

At temperatures above 930 ∘C, PbO reduces PbS to form metallic lead (Pb). The byproduct of the reaction is SO2. Calculate the amount of lead produced (in kg) when a reactor is charged with 887.0 kg of PbS and 1330 kg of PbO.
10. ### Dilution

Please, if possible, check if my method of dilution is correct Problem: Given a very concentrated liquid PBS, dilute it to 1:15,000 My approach is to use serial dilution First: dilute it 15x (50ul of PBS + 750ul of water)... this will …

More Similar Questions