It is now 10:29a.m, but when the bell rings at 10:30a.m. Suzete will be late for french class for the third time this week. She must get from one side of the school to the other by hurring down three different hallways. She runs down the first hallway, a distance of 35.0m at a speed of 3.50 m/s. The second hallway is filled with students and she covers its 48.0-m length at an average speed of 1.20 m/s. The final hallway is empty and suzete sprints its 60.0-m length at a speed of 5.00 m/s.
Doea suzette make it to class ontime or does she get detention for being late again?
distance = rate*time
time for first hallway is
time = distance/rate = 35.0/3.50 = ??
Do time for second hallway and third hallway the same, add the times together, and see if the total adds to more than 1 minute (the difference between 10:29 and 10:30).
To determine whether Suzete makes it to class on time or gets detention, we need to calculate the total time it takes her to run through all three hallways and compare it to the time it takes for the bell to ring.
First, we calculate the time it takes for Suzete to run down the first hallway:
Distance = 35.0 m
Speed = 3.50 m/s
Time = Distance / Speed
Time = 35.0 m / 3.50 m/s
Time = 10.0 s
Next, we calculate the time it takes for Suzete to navigate through the crowded second hallway:
Distance = 48.0 m
Speed = 1.20 m/s
Time = Distance / Speed
Time = 48.0 m / 1.20 m/s
Time = 40.0 s
Finally, we calculate the time it takes for Suzete to sprint through the empty third hallway:
Distance = 60.0 m
Speed = 5.00 m/s
Time = Distance / Speed
Time = 60.0 m / 5.00 m/s
Time = 12.0 s
Now, we add up the times for each hallway to find the total time it takes Suzete to reach class:
Total Time = Time for 1st hallway + Time for 2nd hallway + Time for 3rd hallway
Total Time = 10.0 s + 40.0 s + 12.0 s
Total Time = 62.0 s
Since the total time taken is 62.0 seconds, Suzete will not make it to class on time before the bell rings at 10:30 a.m. and she will likely end up with detention for being late again.
To determine if Suzete makes it to class on time, we need to calculate the total time it takes for her to travel through all three hallways.
First, let's find the time taken to run down the first hallway:
Distance of the first hallway (d1) = 35.0 m
Speed in the first hallway (v1) = 3.50 m/s
Using the formula: time = distance / speed, the time taken in the first hallway (t1) is:
t1 = d1 / v1
t1 = 35.0 m / 3.50 m/s
Next, let's calculate the time taken to cross the second hallway, which is filled with students:
Distance of the second hallway (d2) = 48.0 m
Average speed in the second hallway (v2) = 1.20 m/s
Again, using the formula: time = distance / speed, the time taken in the second hallway (t2) is:
t2 = d2 / v2
t2 = 48.0 m / 1.20 m/s
Lastly, let's calculate the time taken to sprint through the final hallway, which is empty:
Distance of the third hallway (d3) = 60.0 m
Speed in the third hallway (v3) = 5.00 m/s
Using the formula: time = distance / speed, the time taken in the third hallway (t3) is:
t3 = d3 / v3
t3 = 60.0 m / 5.00 m/s
Now, we can calculate the total time taken by summing up the times for each hallway:
Total time (t_total) = t1 + t2 + t3
If the sum of the total time is less than the time between 10:29 a.m. and 10:30 a.m., Suzete will make it to class on time. Otherwise, she will be late and possibly get detention.
Note: The given time difference (from 10:29 a.m. to 10:30 a.m.) is not precise enough to determine if Suzete will be on time or late. We need the exact time difference between her current time and the bell ringing time.