physicsss
posted by confusedd!HELPP!!! .
while driving his sports car at 20.0 m/s down a fourlane highway, eddie comes up behind a slowmoving dump truck and decides to pass it in the left lane. If eddie can accelerate at 5.00 m/s2) (squared) how long will it take for him to reach a speed of 30.0 m/s?
i know its
Vfinal=Vinitial+acceleration*time but i don't know what 5.00 m/s2 (squared) means...
would it be 30.0 = 20.0 + 5.00 m/s^2 (squared) * time, but i have to solve for time..... whats the squared for....? can you write me this equation in numbers so i can just slove it, because i know how it goes just the squared confuses me....

5.00 m/s^2 is the acceleration rate of the passing car. Multiply it by the time interval for the velocity change/ You havew already written the correct equation. Solve if for t.
t = (10 m/s)/(5 m/s^2)
Your answer will be in seconds
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