Please help me through this problem...
A 0.5117 gram fertilizer containing phsphorus was oven dried. The weight of the dried sample is 0.4998 grams. However, 10% moisture is still retained in the sample. Calculate the moisture content in the sample in as received and dry basis. If the sample is completely dried, how much wouldit weigh?
My work:
0.5117-0.4998 = 0.0119 grams -> amount of water removed excluding the 10% left in the sample...I don't know what to do next.
Orgwt*percentsample-(.5117-.4998)= water left, and water left= .1*.4998
or
percentsample= (.0119+.1*.4998)/.5117
and if do not want decimal percent, then muliply by 100
So, the moisture content (as received) is ((0.5117-0.4998)/0.5117)* 100 = 2.326%
and the the moisture content (dry basis) is ((0.1*0.4998)/0.5117)*100 = 9.767%
and when the sample is completely dried, it would weigh 0.4998-(0.1*0.4998) = 0.4498
Am I right?
I am having a problem understanding this problem.
A 0.5117 gram fertilizer containing phsphorus was oven dried. The weight of the dried sample is 0.4998 grams. However, 10% moisture is still retained in the sample. Calculate the moisture content in the sample in as received and dry basis. If the sample is completely dried, how much wouldit weigh?
Is the 10% moisture retained after partial drying 10% of 0.4498 OR 10% of 0.5117.
To calculate the moisture content in the sample on an as-received basis, you need to consider the weight of the moisture that is retained in the sample. In this case, 10% moisture is still retained in the sample.
First, calculate the weight of the moisture retained in the sample:
Weight of the sample = 0.5117 grams
Weight of the dried sample = 0.4998 grams
Weight of the retained moisture = Weight of the sample - Weight of the dried sample
Weight of the retained moisture = 0.5117 grams - 0.4998 grams
Weight of the retained moisture = 0.0119 grams
Now, to calculate the moisture content on an as-received basis, divide the weight of the retained moisture by the weight of the sample:
Moisture content on the as-received basis = (Weight of the retained moisture / Weight of the sample) * 100
Moisture content on the as-received basis = (0.0119 grams / 0.5117 grams) * 100
Moisture content on the as-received basis = 2.325%
To calculate the moisture content on a dry basis, you need to consider the weight of the dried sample.
Moisture content on the dry basis = (Weight of the retained moisture / Weight of the dried sample) * 100
Moisture content on the dry basis = (0.0119 grams / 0.4998 grams) * 100
Moisture content on the dry basis = 2.381%
Finally, to find out the weight of the completely dried sample, you need to subtract the weight of the retained moisture from the weight of the dried sample:
Weight of completely dried sample = Weight of the dried sample - Weight of the retained moisture
Weight of completely dried sample = 0.4998 grams - 0.0119 grams
Weight of completely dried sample = 0.4879 grams
Therefore, the completely dried sample would weigh 0.4879 grams.