calculus
posted by wendy .
find the first derivative of
f(t)= (1t)^(1/2)

f(t)= (1t)^(1/2)
chain rule
f'(t)= 1/2(x)^(1/2)dx
x= 1t
dx= 1
f'(t)= 1/2(1t)^(1/2)(1)
f'(t)= (1/2)(1t)^(1/2)
f'(t)= 1/(2sqrt1t)
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