Math- Calculus

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Find an equation of the line that is tangent to the graph of f and parallel to the given line

Function: f(x) = x^3
Line 3x-y+1 = 0

._.; I know the derivative of the function is 3x^2 and I do have the answer in the back of my book just need the way to get it..

  • Math- Calculus -

    Sorry in advance-- I don't know how to find the answer, but I'm willing to help all I can.

    First, rearrange the equation of the line to make it y=-3x-1. Since we need to find a line parallel to this one, we know it needs a slope of -3.

    y=-3x-1
    y=mx+b
    m=slope
    m=-3

    What is the answer the back of the book gives? Sometimes it's possible to work backwards from the answer.

    Sorry that's as far as I could go.
    I'll try to help you out all I can--I'm trying to work it out right now.

    --Cori

  • Math- Calculus -

    :3 yep I got there too.
    It was y=3x+2 I think.

    It doesn't matter though XD I'll just ask my teacher when I get there

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