I need help with the following problem:
Solve the equation:
(x/2x+2)= (-2x/4x+4) + (2x-3/x+1)
I am not sure whether I am interpreting your question correctly.
.5x + 2 = -.5x + 4 + 2x - 3/x + 1
First, get all the x terms on one side.
.5x + .5x - 2x + 3/x = 4 + 1 - 2
Combine terms.
-x + 3/x = 3
Multiply both sides by x to get rid of x in the denominator.
-x^2 + 3 = 3x
Transpose.
-x^2 - 3x + 3 = 0
Multiply by -1.
x^2 + 3x - 3 = 0
Unfortunately, I cannot factor this to find possible answers. Are there any typos in your equation?
I hope this helps a little. Thanks for asking.
n(5^2x1/25)=3
lol sorry i was suppose to give you the answer..i have never done this before...
To solve the equation, we need to find the value of x that satisfies the given equation. Let's simplify the equation step by step.
First, let's simplify each fraction on the right side of the equation:
(x/2x+2) = (-2x/4x+4) + (2x-3/x+1)
To simplify the fractions, we need to find their common denominators.
The common denominator for 2x+2 and 4x+4 is 2(x+1). Multiplying the numerator and denominator of the first fraction by (x+1), we get:
[(x/2x+2) * (x+1)] = (-2x/4x+4) + (2x-3/x+1) * (2x+1)
Simplifying further, we have:
(x(x+1)/(2(x+1))) = (-2x/4(x+1)) + ((2x-3)(2x+1)/(x+1))
Now, let's simplify the equation further by clearing the denominators:
x(x+1) = -2x + (2x-3)(2x+1)
Expanding the parentheses and combining like terms, we have:
x^2 + x = -2x + 4x^2 - x - 3
Rearranging this equation, we have:
x^2 + x = 4x^2 - 2x - 3
Next, let's move all terms to one side of the equation:
x^2 - 3x^2 + x + 2x - 3 = 0
Combining like terms, we get:
-x^2 + 3x - 3 = 0
To solve this quadratic equation, we can either factor it or use the quadratic formula. Let's use the quadratic formula: x = (-b ± √(b^2 - 4ac)) / (2a)
In this case, a = -1, b = 3, and c = -3.
Substituting the values into the quadratic formula, we have:
x = (-(3) ± √((3)^2 - 4(-1)(-3))) / (2(-1))
Simplifying further, we have:
x = (-3 ± √(9 - 12)) / (-2)
x = (-3 ± √(-3)) / (-2)
Since we have a square root of a negative number, the equation has no real solutions. Hence, there are no values of x that satisfy the given equation.