Algebra
posted by Soly .
I have some problems that I am having trouble with and I have some that need checking please. Thanks!
Solve the equation.
4. (x+7/4)=2(x1/6)
Find all the value(s) of x that make thedenominator(s) zero. Then solve the equation.
6. (x8/2x) +5= (x+6/x)
Solve the equation.
7.(x/2x+2)= (2x/4x+4) + (2x3/x+1) on thie problem I got 9/4
Determine whether the equation is an identity, a conditional equation, or inconsistent equation.
13. 2(x+7)+52=4x6(x+3) I got inconsistent equation
16. (3x+2/(4) +2=(7x/2) I got inconsistent equation.
Solve the radical equation, and check all proposed solutions.
3. ãx+2=8 I got 62 for this one
5. xã3x2=4
Solve and check the equation.
7. (x^2+14x+49)^3/4 20=7
Solve the equation by making an appropriate substitution.
16. x^413x^2+36=0 I got {2,3} for the soultions.
19. (4x3)^210(4x3)+24=0 This one I am not too sure how to do it.
Solve the absolute value equation or indicate that the equation has no solution.
25. 8x+9 +5=9 I got 5/8
27. x^24x+4=2 I got x=2
Solve the radical equation, and check all proposed solutions. (I went and corrected these cause my square root symbol didn't show up)
3. square root of x+2=8 I got 62 for this one
5. x square root of 3x2=4
#3 ok
#5
x4 = sqrt(3x2)
square both sides
x^28x+16=3x2
x^211x+18+0
(x9)(x2)=0
x=9 or x=2
Now both answers have to be checked since we squared the equation. 9 works but 2 does not
#6
Is it like this?
((x8)/2x) +5= ((x+6)/x)
To start x cannot be equal to zero
multiply by 2x
x8 + 10x = 2x+12
x=20/9
I will do a few more, but not all,
Please split your post up into smaller parts
#19. (4x3)^210(4x3)+24=0
let y=4x3 so now we have y^2  10y +24 = 0
(y6)(y4)=0
then y=6 or y=4, but y=4x3
so now 4x3=6
x=9/4
or
4x3=4
x=7/4
#25.
8x+9 +5=9
8x+9 =4
then 8x+9=4 or 8x9=4
x=5/8 (like you had) OR x=13/8
Respond to this Question
Similar Questions

Substitution MethodPlz help
Use the Substitution method to solve the system of equations. x + y = 4 x  y = 2 solve for x in the second equation. x= y+2 Put that in for x in the first equation: x+y=4 (y+2) + y = 4 solve for y. Then, x= y+2 i don't get it.How … 
Algebra 2
would some one please check these for me 1. divide x^236y^2 over 5x^2+30y divide (x^26xy) A: x+6y over (5x)(x^2+6y) 2. Add. Express your answer in simplest form. 2x 0ver x^2+15x+54 + 4over x+6 A: 6 over x+9 3. solve: (9 over x5) … 
Algebra II
I need some help with some problems as well as need some checked. Could you please help me? 
Algebra......Help Quick!!
12a^3bc18a^2bc^2+6a^2c, x^2+20x+36, 12x^48x^34x^2, x^2+36x, 9x^2+6x+1, 6x^3+11x10, x^2+3x6..............can someone please help me solve some of these problems if not all. I have forgotten how to solve them can someone please … 
Math
I need help with these three problems. They are on a Study Guide and I need some refreshing up of how to do them. 17. Solve the equation using the zero product property... 8n(5n+3) 19. Solve the equation by factoring 5z^22z3=0 20. … 
math
I need help with these three problems. They are on a Study Guide and I need some refreshing up of how to do them. 17. Solve the equation using the zero product property... 8n(5n+3) 19. Solve the equation by factoring 5z^22z3=0 20. … 
Math
I need help with these three problems. They are on a Study Guide and I need some refreshing up of how to do them. 17. Solve the equation using the zero product property... 8n(5n+3) 19. Solve the equation by factoring 5z^22z3=0 20. … 
Algebra
I have four problems I'm having trouble with. I need to solve the equations by completing the square. 1) w^2  5w = 11/4 2) z^2 + 11z = 21/4 3) k^2  8k  7 = 0 4) v^2  7v + 1 = 0 
Algebra 2 Honors
Well, I'm having trouble on some of my homework questions and looking to get help as soon as possible on one of them about inverse variation. 1. If y varies inversely as x and y = 3 when x = 9, find y when x = 81. I will use the equation … 
Algebra
I'm having trouble with these problems, I'm not asking for just the answers, I need to know how to solve them, its a practice for my upcoming final, So I need to know how to do them. Name the property of real numbers illustrated. (2√7)*√3=2(√7*√3) …