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physics # 5

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5. The length of a simple pendulum with a period on Earth of one second is most nearly

a.) 0.12 m
b.) 0.25 m
c.) 0.50 m
d.) 1.0 m
e.) 10.0 m


The formula for the period is
P = 2 pi sqrt(L/g)
g is the acceleration of gravity, 9.8 m/s^2.
Solve for L. (or get out a piece of string and do the experiment.)

  • physics # 5 -

    Pendulum period in seconds
    T ≈ 2π√(L/g)
    L is length of pendulum in meters
    g is gravitational acceleration = 9.8 m/s²
    Length for 1 second = 0.248 m
    (b)

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