math-differential equations

posted by .

hi i need to know how to do this one
thanks

Find the solution to yx + x + (dy/dx) = 0 ; y(9) = -9

y = ????

Does this separate the variables?

dy/dx=-x(y+1)

dy/(y+1) = -x dx

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Differential Equations

    Find the general solution of the differential equation specified. 1) dy/dt= 1/(ty+1+y+1) 2) dy/dx=sec y I got y(x)=arcsin(x) for the second one. I'm not sure what to do with the first one.
  2. differential equations

    solve the differential equation by seperation of variables 5. y'=xy/2ln y
  3. calculus

    Please help. How do I separate the variables in the following differential equation dy/dx=(2/27)(x-3)then square root (x^2-6x+23)/y where (y>0). Then give general solution in implicit form. Thank you so much if you can help.
  4. Differential Equations

    Consider the differential equation: dy/dt=y/t^2 a) Show that the constant function y1(t)=0 is a solution. b)Show that there are infinitely many other functions that satisfy the differential equation, that agree with this solution when …
  5. Differential Equations

    Consider the differential equation: dy/dt=y/t^2 a) Show that the constant function y1(t)=0 is a solution. b)Show that there are infinitely many other functions that satisfy the differential equation, that agree with this solution when …
  6. Calculus

    dy/dx = 4ye^(5x) a) Separate the differential equation, then integrate both sides. b) Write the general solution as a function y(x). For the second part, I got y(x)=e^((5e^(5x))/(5)) + C but I don't understand how to separate differential …
  7. math

    y′=(2y+x)/x, y(1)=4 1. The resulting differential equation in x and u can be written as xu'=------ 2.Separating variables we arrive at -----du= dx/x 3.Integrating both sides and simplifying, the solution can be written in the …
  8. Calculus - Differential Equations

    Use separation of variables to find the solution to the differential equation: 4 (du/dt) = u^2, subject to the initial condition u(0)=6.
  9. Calculus - Differential Equations

    Use separation of variables to find the solution to the differential equation: 4 (du/dt) = u^2, subject to the initial condition u(0)=6. So far, I have: 4 du = u^2 dt 4/u^2 du = dt -4/u = t+C I am unsure what to do from this point...
  10. Differential equations,Calculus

    So I have the following differential equation. The general solution I have is: t=k(-1/r)+c I now need to find the particular solution when t=0 and the radius (r) = 1cm. So k is a constant which is approx 3.9 (5/4pi) So for the particular …

More Similar Questions