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Is it possible for AB = 10, BC = 2x + 5 and AC = 5x, given that point B is the midpoint

No. I answered the same question last week.

The total length of 10 would have to be equal to 7x + 5. That means
7x = 5
x = 5/7
You have an additional requirement that
2x + 5 = 5x, since B is the midpoint.
This requires
3x = 5; x = 5/3

These two requirements cannot both be satisfied.

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