algebra
posted by carla .
I worked the problem out, but could you check my work over and see if it's correct? I used the quadratic formula.
2x^2+10x+11
a=2 b=10 c=11
x=10(plus or minus) sqrt 10^24(2)(11)
over 2(2)
10(plus or minus) sqrt 100  8(11)
over 4
10(plus or minus) sqrt 10088
over 4
10(plus or minus) sqrt 12
over 4
FINAL ANSWER:
10(plus or minus) 2 sqrt 3
over 4
can this be simplified any more? or is the final answer even correct? pls help!!
Divide the 2a out, so
x= 2.5 + .5* sqrt3
I'm a little confused. could you show me where exactly I went wrong? thanks! :)
When you used the formula
x = [b +/ sqrt (b^24ac)]/2a, you forgot to divided by 2a, which is 4.

f
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