Algebra
posted by PLEASE HELP .
Solve by using the quadratic formula
x^2=7x+12
First, put all the terms on one side.
x^2=7x+12
x^2 + 7x 12 = 0
If the original sign for the 12 were negative, this would lead you to:
x^2 + 7x + 12 = 0
This could factor into:
(x+3)(x+4) = 0
However, as you have formula posted, it cannot be factored.
I hope this helps. Thanks for asking.
x=(7/2)+(sq97)/(2),(7/2)(sq97)/(2)
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