Post a New Question

Calculus

posted by .

Given the differential equation:
dy/dx = y(1+x), y(0)=1,
Use Euler's method with step size .1 to approximate y(.3).

y' = y(1+x), y'(0) = 1(1+0)=1
->the solution has slope 1 at the point
(0,1); x0=0, y0=1, h=0.1, F(x,y)=y(1+x)

y1=y0+h*F(x0,y0)
y1=1 + 0.1(1(1+0))
y1=1.01

y2=1.01 + 0.1(1.01(1+0.1)
y2=1.02111

y3=1.02111 + 0.1(1.02111(1+0.2))
y3=1.1436432

Is this the answer or am I going about this the wrong way? If so, please steer me in the right direction. Thanks.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question