Algebra
posted by Tomika .
Find two consecutive positive integers such that the sum of the square is 85..(show your work)
If X is the first integer, then X+1 is the next; therefore, the sum of those squares will be 85.
X^2 + (X+1)^2 = 85
Solve for X, then add 1 to it for the second integer.
Post your work if you get stuck.
I am stuck that is why I posted on here for assistance..
I wrote the equation for you. The rest is just algebra. All you need to do is to solve for X. If you don't know how, tell me what you don't understand about the next step.
I was confused in where you said to add 1, would you still use the quadratic formula to solve the equation?
If X is the first integer, then X+1 is the next; therefore, the sum of those squares will be 85.
X^2 + (X+1)^2 = 85
Solve for X, then add 1 to it for the second integer.
X^2 + X^2 + 2X + 1 = 85
2X^2 + 2X 84 = 0
Now use the quadratic formula.
You should get X = 6, then X+1 = 7 so the two integers are 6 and 7.
Thank you very much!!!
Respond to this Question
Similar Questions

math, algebra
2a+2ab+2b I need a lot of help in this one. it says find two consecutive positive integers such that the sum of their square is 85. how would i do this one i have no clue i know what are positive integers.but i don't know how to figure … 
algebra
Find two consecutive positive integers such that the sum of their squares is 85. n^2+(n+1)^2+2n = 85 n^2+n^2+2n+1=85 2n^2+2n=84 n^2+n=42 n^2+n42=0 (n6)(n+7)=0 n=6 n=7 Is my work and answer correct? 
math
there are three consecutive positive integers such that the sum of the squares of the smallest two is 221. write and equation to find the three consecutive positive integers let x= the smallest integer 
Algebra
The difference of the cubes of two consecutive odd positive integers is 400 more than the sum of their squares. Find the sum of the two integers. 
Math
find three consecutive positive odd integers such that the sum of the squares of the first and second integers is equal to the square of the third integer minus 7? 
math
What is the smallest of three consecutive integers if the sum of the smaller two integers is equal to 177 less than four times the largest? 
math
What is the smallest of three consecutive integers if the sum of the smaller two integers is equal to 177 less than four times the largest? 
math
What is the smallest of three consecutive integers if the sum of the smaller two integers is equal to 177 less than four times the largest? 
math please help
Three consecutive odd intergers are such that the sum of the squares of the first two integers is 54 more than 20 times the third integer. Determine the three integers. Please help and show all work thank you 
MATH PLEASE SHOW WORK
Three consecutive odd intergers are such that the sum of the squares of the first two integers is 54 more than 20 times the third integer. Determine the three integers. Please help and show all work thank you SHOW WORK SO I UNDERSTAND …