Simplfing Fractions
posted by Toni .
Three problems I need to know if I am correct or not if not I will place how I got the answer and maybe some one can show me where I messing up aT
Simplify
1+2/3 over top 2+1/2
My answer
was 2/3 to me it does not seem right If I am wrong please let me know i will put all the steps I did to get this and maybe you can help me see where I did it wrong
2nd question
m^5/4 over top of m^7/16
My answer was 4/m^3
3rd question
3/x5 +1 over top of 1 4/x5
My answer is x2/x9
1+2/3 over top 2+1/2
My answer
was 2/3 to me it does not seem right If I am wrong please let me know i will put all the steps I did to get this and maybe you can help me see where I did it wrong
I agree with the answer of 2/3 if the problem is([1 + (2/3)]/[2 + (1/2)] =
2nd question
m^5/4 over top of m^7/16
My answer was 4/m^3
For (m^{5}/4)/(m^{7}/16) = I get the 4 but not over m^{3}.
3rd question
3/x5 +1 over top of 1 4/x5
My answer is x2/x9 I can't tell what the problem is without parentheses.
Lets do the numerator: 1+ 2/3= 5/3
Now the denominator: 5/2
5/3 / 5/2 which is the same as (remember that multiplying the reciprocal is the same as divideing..
5/3 * 2/5 = 5*2/3*5= 2/3 So it is right. Good work.
On the second,
m^5/4 divided by m^7/16 changes to
M^5/4 * 16/m^7 or
m^5/4 * 16* m^7
4 m^2 or 4/m^2
Last:
3/(x5) + 1 or (3+x5)/(x5) is numerator.
Now, for denominator,
that changes to (x5 4)/(x5) or
(x9)/(x5)
so numerator /denominator changes to a multiply by
numerator * (1/denominator) or
(3+x5)/(x5) * (x5)/(x9) or
(x2)/(x5) and you are correct.

Simplfing Fractions 
dom
Find of 12. Express your answer in simplest form.
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