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Question: Find the expected freezing point of a water solution that contains 286g of aluminum nitrate (Al(NO3)3) in 8.5 kg of water. answer in celcius

Note the correct spelling of Celsius.
delta T = i*Kf*m
Determine the molality of 286 g Al(NO3)3 in 8.5 kg water. (molality = mols solute/kg solvent).Plug that in for molality in the freezing point equation I wrote first. You have Kf, the freezing point constant for water, you have molality, and i is the number of particles (in this case that is 4; i.e., 1 Al and 3 nitrate ions). Post your work if you get stuck.

To find the expected freezing point of the water solution, we need to calculate the molality of aluminum nitrate (Al(NO3)3) in the water first.

Step 1: Calculate the moles of Al(NO3)3.
To do this, we first need to find the molar mass of Al(NO3)3:
Aluminum (Al) has a molar mass of 26.98 g/mol.
Nitrate (NO3) has a molar mass of 62.01 g/mol.
Therefore, the molar mass of Al(NO3)3 is:
(1 * 26.98 g/mol) + (3 * 62.01 g/mol) = 26.98 g/mol + 186.03 g/mol = 213.01 g/mol.

Now we can calculate the moles of Al(NO3)3:
286 g / 213.01 g/mol = 1.34 mol.

Step 2: Calculate the molality of Al(NO3)3 in the water.
Molality (m) is defined as moles of solute per kilogram of solvent.
Given that there are 8.5 kg of water, we can use the formula:
Molality = moles of solute / kilograms of solvent.

Molality = 1.34 mol / 8.5 kg = 0.1578 mol/kg.

Step 3: Calculate the freezing point depression.
The equation for freezing point depression is:
delta T = i * Kf * m
Where:
delta T is the freezing point depression (change in temperature from the normal freezing point),
i is the number of particles in the solute (in this case, Al(NO3)3), which is 4 because it dissociates into one Al ion and three nitrate ions,
Kf is the freezing point constant for water, which is approximately 1.86 °C/m, and
m is the molality of the solute.

Plugging in the values:
delta T = 4 * 1.86 °C/m * 0.1578 mol/kg
delta T = 1.47 °C

Step 4: Calculate the expected freezing point.
The expected freezing point is the normal freezing point of water (0 °C) minus the freezing point depression:
Expected Freezing Point = 0 °C - 1.47 °C = -1.47 °C.

Therefore, the expected freezing point of the water solution containing 286g of aluminum nitrate (Al(NO3)3) in 8.5 kg of water is approximately -1.47 °C.