math/algebra1a
posted by Confused
write the equation of the line which has yintercept (0,5) and is perpendicular to the line with equation y=3x +1
a) y=3x + 5
b) y= 1/3x + 5
c) y= 3x + 5
d) y= 1/3x + 5
The slope of the 2nd equation is 3...because the equation of a line is y=mx+b, where "m" is the slope and b is the yintercept. So since the slope of the given equation is 3. To get the slope of the line perpendicular to that, you would get the negative reciprocal of 3.
3 is 3/1. You would flip it to 1/3 and multiply by 1 to get 1/3 to get your perpendicular slope. And since the yintercept is (0,5), you only need the yvalue, which is 5.
So your equation would be y=1/3x + 5.
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