Given g(x) = –2x – 1, find g(3a).

G(3a)=-2(3a)-1
= -6a-1
= -5
is this right or do I just stop at -6a-1

Just stop at -6a-1

Matt

Also, let me add this.

If you have -6-1 (without the "a") that would be -7. Not -5.

But -6a-1 is the correct answer for this problem.

Matt

thank you for clearing this up for me.

:-) Glad I could help.

You're welcome! I'm glad I could clear that up for you. It's important to remember that when evaluating a function, you substitute the given value into the function and simplify the expression. In this case, you correctly substituted 3a into g(x) and simplified to -6a-1. This is the final answer, and there is no need to simplify it further. The result is an expression with the variable 'a' that represents the value of g(3a). If the expression had no 'a' in it, then you would simply evaluate it to get a numerical value. But in this case, you stop at -6a-1 since it cannot be simplified any further.