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consider the function g(x)=x^3+5x^2-4x+4.determine:

1)g(37)

2)the value of x between zero and a hundred such that g(x)=145456

how do i do this?

1) put in 37 for x, and compute.

2) put in 145456 in for g(x), and solve for x.

for the first one, just substitute 37 for x and evaluate

for the second one
x^3 + 5x^2 - 4x + 4 = 145456
x^3 + 5x^2 - 4x - 145452 = 0

at this point you will need a programmable calculator which solves any equation, or
use Newton's Method, or
go to an online "equation solver"

I went to
http://www.hostsrv.com/webmab/app1/MSP/quickmath/02/pageGenerate?site=quickmath&s1=equations&s2=solve&s3=basic
and it gave me an exact value of x=51

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