Algebra
posted by Helpless Again .
I am stuck, pleas help, i have the example but I am still not able to figure it out...
Find the value of X...5/x+6+2/x^2+7x+6=3/X+1
Find the value of X...2/5=x2/20
First, get the X terms on one side of the equation and the numbers on the other.
2/5=X2/20
2/5+2/20 = X
Change the numbers to get a common denominator.
4/10+1/10 = X
Combine and reduce.
X = 5/10 = 1/2 = .5
5/x+6+2/x^2+7x+6=3/X+1
Get the X terms on one side of the equation and the numbers on the other.
5/X+2/X^2+7X3/X = 11
Multiply both sides by X^2.
5X+2+7X^33X = 11X^2
Again, get the X terms on one side of the equation and the numbers on the other.
7X^3+11X^2+2X = 2
X(7X^2+11X+2) = 2
Unless there are typos in your equation, this as much as I can do.
I hope this helps. Thanks for asking.
Thank you very much!!
Thank You!!!
"Helpless again", see how the lack of proper brackets can wreck a question.
PsyDAG followed the order of operation exactly the way you typed it, and it led to a point where we cannot solve the equation.
Had you typed it the way it was probably meant to be...
5/(x+6) + 2/(x^2 + 7x + 6) = 3/(x+1)
the second term factors at the bottom
5/(x+6) + 2/((x+1)(x+6)) = 3/(x+1)
multiplying every term by (x+1)(x+6)...
5(x+1) + 2 = 3(x+6) now it's a little grade nine equation for
x=11/2
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