caculus
posted by jimmy .
A rectangle is inscribed with its base on the xaxis and its upper corners on the parabola y=11x^2. What are the dimensions of such a rectangle with the greatest possible area?
Width=? Height=?
Area= height*width=y(2x)
Area=(11x^2)(2x)
solve for dArea/dx, set to zero, solve for x. Width will be 2x, height y.
ty very much!
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