intro cal
posted by Emma .
the first 3 term of a geometric progression are
k4, 2k4, 4k+4.
what is the value of k?
can someone help please!
in any geometric progression any term divided by its previous term gives you the common ratio, so ....
(2k4)/(k4) = (4k+4)/(2k4)
crossmultiply and proceed.
I comes out nice, the square term cancels.
how do i cross multiply this?i get confused easiy when doing cross multiply in division...
(2k4)(2k4) = (k4)(4k+4)
4k^2  16k + 16 = 4k^2  12k  16
4k = 32
k=8
ooh so you times it by the opposite!silly me...
Thank you soo much!!
yes, in general
a/b = c/d > bc = ad
try it with equivalent fractions
we know 2/3 = 10/15
then 2*15 = 3*10 ...true!
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