Can someone solve these for me?Can someone correct meif I didn't type these right

1.(m-2)/(m-5)*(m+5)/(m-2)
2.4(x+2)/5x*(6x^2)/2x
3.(25-x^2)/12*6/(5-x)
4.(a^2-9)/a^2*(a^2-3a)/(a^2+a-12)
5.(5x-5)/(16)/(x-1)/6
6.(6-3x)/(5)/(4x-8)/25
7.(x^2-9)/(4X+12)/(x-3)/6
8.(x^2+13x+12)/(x+2)/(x+1)

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I assume you mean
3.[(25-x^2)/12] * [6/(5-x)]
Facctor 25 - x^2 into (5-x)(5+x).
Then cancel out the 5-x terms that appear in the denominator of one term and the numerator of the other. The 6/12 can also be reduced to 1/2.

x2-8x+7/x2+6x-7

.(m-2)/(m-5)*(m+5)/(m-2)

12^an/x^2n^4*6x^7n^5/9a^5n^2

To simplify the expression, you can factor the numerator and denominator:

Numerator: x^2 - 8x + 7 = (x - 1)(x - 7)
Denominator: x^2 + 6x - 7 = (x + 7)(x - 1)

Now, you can cancel out the (x - 1) term in both the numerator and denominator:

(x - 1)(x - 7)/(x + 7)(x - 1)

Finally, you are left with:

(x - 7)/(x + 7)

To simplify the expression (m-2)/(m-5) * (m+5)/(m-2):

1. First, simplify each individual fraction. (m-2) can cancel out in the numerator and denominator of the first fraction, leaving 1. Similarly, (m-2) can cancel out in the numerator and denominator of the second fraction, leaving 1.

2. After simplifying each fraction, you are left with (m+5)/(m-5).

So the simplified expression is (m+5)/(m-5).

To simplify the expression 4(x+2)/(5x) * (6x^2)/(2x):

1. Simplify each individual fraction. In the first fraction, 4 can be canceled out with 2 in the second fraction, leaving 2. Similarly, (x+2) can be canceled out with (2x) in the second fraction, leaving (x).

2. After simplifying each fraction, you are left with 2(x)/(5x) * 6x^2 = 2x/(5x) * 6x^2.

To simplify the expression (25-x^2)/12 * 6/(5-x):

1. Factor 25 - x^2 into (5-x)(5+x).

2. Cancel out the (5-x) terms that appear in the denominator of one term and the numerator of the other. This leaves (5+x)/12 * 6/(5-x).

3. Simplify each fraction and you get (5+x)/2 * 1/(5-x).

To simplify the expression (a^2-9)/a^2 * (a^2-3a)/(a^2+a-12):

1. Factor a^2 - 9 into (a-3)(a+3). Similarly, factor a^2 - 3a into a(a-3).

2. Cancel out the (a-3) terms that appear in the numerator of one term and the denominator of the other, leaving (a+3)/a^2 * a/(a^2+a-12).

To simplify the expression (5x-5)/(16)/(x-1)/6:

1. Simplify each individual fraction. In the first fraction, (16) can be canceled out with (6) in the second fraction, leaving 2/3.

2. After simplifying each fraction, you are left with (5x-5)/(2/3)/(x-1).

To simplify the expression (6-3x)/(5)/(4x-8)/25:

1. Simplify each individual fraction. In the first fraction, (5) can be canceled out with (25) in the second fraction, leaving 1/5.

2. After simplifying each fraction, you are left with (6-3x)/(1/5)/(4x-8).

To simplify the expression (x^2-9)/(4x+12)/(x-3)/6:

1. Simplify each individual fraction. In the first fraction, (4x+12) can be canceled out with (4) in the second fraction, leaving (x+3)/1.

2. After simplifying each fraction, you are left with (x^2-9)/(x-3)/6.

To simplify the expression (x^2+13x+12)/(x+2)/(x+1):

1. Simplify each individual fraction. In the first fraction, (x+2) can be canceled out with (x+2) in the denominator, leaving 1. Similarly, (x+1) can be canceled out with (x+1) in the denominator, leaving 1.

2. After simplifying each fraction, you are left with (x^2+13x+12)/1/1.

So the simplified expression is (x^2+13x+12)/1/1.