# algebra2

posted by Tina

Solve each of the following quadratic equations.
can some explain how to do these kinds of problems

4x^2=13x+12

i believe if i am understanding this i am supose to add to where i get =0
4x^2-13x+12=0
now what do i need to do
I am thinking factoring but I am not sure how to do this part

4x^2 - 13x - 12 = 0

It does factor, I will give you a hint:
one of the factors is x-4

You must have been taught at least one general method to factor those quadratics that do factor.

It has been a while since i worked with any algebra
but i think i can remember some so this is what i got see if i am correct please
4x^2-13x-12=0
(4x+3)(x-4)=0
4x+3=0 0r x-4=0
4x=-3
4x/4=-3/4
x=-3/4

x-4=0
x=4

(-3/4,4)

did i do this right

yes, good for you.

it seems to be correct

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