# math

posted by .

the length of a rectangle is 6 cm more than its width. the area is 11 cm squared. find the length and width.

look at the post by anonymous at 8:55, it is almost the same as yours.
Do it the same way.

length= x+6
width=x

x(x+6)=11
x^2 + ^x =11
x^2+6x-11=0
(x-_)(x-_)

solve for x.

Then substute the x for the length and width.

• math -

l=6+x, w=x,a= 11cm2 , area of rectangle= length*width , 11CM2=X(X+6), X2+6X=11,X2+6X-11=0

• math -

l=6+x, w=x,a= 11cm2 , area of rectangle= length*width , 11CM2=X(X+6), X2+6X=11,X2+6X-11=0, I GOT - 43 AND 43 BY AX2+BX+C=0

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