posted by .

intergral of (x^3 -4x + 3)/(2x) dx

would this be ln abs(x^3-4x+3) + C?
I don't really understand how to solve this problem.

d/dx (tan (x^2))


would this be the correct answer to find the derivative of tan (x^2)?

no, because if you differentiate your answer you don't get what you started with.

divide the 2x into each term so that your expression becomes

(1/2)x^2 - 2 + 3/(2x)

now the integral of that is

(1/6)x^3 + 2x + (3/2)lnx + c

yes, to your derivative of tan x^2

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Integration

    Intergrate ¡ì sec^3(x) dx could anybody please check this answer. are the steps correct?
  2. Calculus - Integration

    Hello! I really don't think I am understanding my calc hw. Please help me fix my errors. Thank you! 1. integral from 0 to pi/4 of (tanx^2)(secx^4)dx It says u = tan x to substitute So if I use u = tan x, then my du = secx^2 then I …
  3. Calc 2

    Ok, I have two questions first: 1. I'm asked to find a cartesian equation for the polar graph of this polar equation: r^2 = sin(2(theta)) The answer I got was (x^2+y^2)^2/(2xy) = 2 Is this the correct way to express it?
  4. integral confusion

    integral of Sec[2x]Tan[2x] i know u is sec 2x du=2sec2xtan2x dx what would i have to multiply with du so it would equal tan 2x dx?
  5. Calculus

    Calc length of arc of y=ln(x) from x=1 to x=2 ---- So far: Definite Integral over x=(1,2) of sqrt(1 + 1/x) dx 1/x = tan^2 t x = 1/tan^2 t sqrt(1+1/x) = sqrt(1+tan^2 t) = sec t dx = -2 * tan^-3 t * sec^2 t dt Integrate over x=(1,2): …
  6. math

    would this be a correct proof of the cauchy-schwartz inequality: abs=absolute value abs(u*v) is less than or equal to abs(u)*abs(v). Then you divide both sides by abs(u)*abs(v) so that you get cos(theta) is less than or equal to 1.
  7. Calc

    y= cube root (1+tan(t)) OR y= (1+tan(t))^(1/3) The answer I got was y'= (1/3)(1+tan(t))^(-2/3)*(sec^2(t)) Is this correct?
  8. calculus (check my work please)

    Not sure if it is right, I have check with the answer in the book and a few integral calculators but they seem to get a different answer ∫ sec^3(x)tan^3(x) dx ∫ sec^3(x)tan(x)(sec^2(x)-1) dx ∫ tan(x)sec(x)[sec^4(x)-sec^2(x)] …
  9. calculus

    So I am suppose to evaulate this problem y=tan^4(2x) and I am confused. my friend did this : 3 tan ^4 (2x) d sec^ 2x (2x)= 6 tan ^4 (2x) d sec^2 (2x) She says it's right but what confuses me is she deriving the 4 and made it a three?
  10. Math Help

    Hi! I need help with this practice problem. My teacher gave us the answer, "2cot u" BUT she wants us to figure out why that's the correct answer. I'm having some trouble with this and could really use some help. Thank you! Problem: …

More Similar Questions