Math: Algebra2 Logarithms
posted by UnstoppableMuffin .
Can someone help me find the value of B in this expression????
log 64 = Blog 4
5 5
Grrr... sorry about that.
Here's the expression again:
log (base = 5) 64 =B log (base = 5) 4
log 64 (base5) = log 4^b (base5)
so 64 = 4^b
by recognition of 64 as a power of 4, b=3

prove that olg base7(9)*log base5(7)*log base3(5)=2