# Math: Algebra2 Logarithms

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Can someone help me find the value of B in this expression????

log 64 = Blog 4
5 5

Here's the expression again:

log (base = 5) 64 =B log (base = 5) 4

log 64 (base5) = log 4^b (base5)

so 64 = 4^b
by recognition of 64 as a power of 4, b=3

• Math: Algebra2 Logarithms -

prove that olg base7(9)*log base5(7)*log base3(5)=2

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