math
posted by help me again(last one) .
the height of a triangle is 4 inches greater than twice its base. the area of the triangle is 168 square inches. what is the base of the triangle?
Area=1/2 B*H= 1/2 B (2B+4)
solve for B
h = 4 + 2b
b = ?
A = (b*h)/2 = 168
168 = [b(4+2b)]/2
168 = (4b + 2b^2)/2
336 = 4b + 2b^2
2b^2 + 4b  336 = 0
2(b^2 + 2b  168) = 0
2(b12)(b+14) = 0
b=12 and b=14
Ignore the negative answer, negative distances have no real meaning.
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