math
posted by relle .
Hi. I'm having trouble with the summation of n from i=2 of ((2^ni)(2^n)). Any help would be greatly appreciated!
the way I am reading the question you have i is going from 2 to n
so there will be n1 terms
using i = 2,3,4,..,n
I get 2^(2n2) + 2^(2n2) + ...
Sum of n terms of a geometric series is
a(1  r^n)/(1r)
so a= 2^(2n2), r = 2^(1) and the number of terms is n1
and the sum is
2^(2n2)[1  2^(1)] / 12^(1))
.
.
.
=2^(n1)(2^n  1)
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