a coordination compound of cupric ion can be described asa Cu(NH3)x SO4. it is known to be 29.9% NH3. what is the value of X?
4. Check it to see if that gives 29.9% NH3.
To determine the value of x in the coordination compound Cu(NH3)xSO4, we are given that the compound is known to be 29.9% NH3. Here's how we can calculate the value of x:
1. Start by assuming x is a whole number and let's call it "n". So, the formula for the coordination compound becomes Cu(NH3)nSO4.
2. Determine the molar mass of NH3 (ammonia) and SO4 (sulfate). The molar mass of NH3 is 17.03 g/mol (1 nitrogen atom + 3 hydrogen atoms) and the molar mass of SO4 is 96.06 g/mol (1 sulfur atom + 4 oxygen atoms).
3. Calculate the molecular weight of Cu(NH3)nSO4 by adding the molar masses of each component: Cu (copper) has a molar mass of 63.55 g/mol, NH3 has a molar mass of 17.03 g/mol, and SO4 has a molar mass of 96.06 g/mol.
4. Multiply the molar mass of NH3 by "n" (the assumed value of x) and divide it by the molecular weight of Cu(NH3)nSO4. Then, multiply the result by 100 to obtain the percent composition of NH3 in the compound.
percent NH3 = (n * molar mass of NH3) / molecular weight of Cu(NH3)nSO4 * 100
In this case, the percent composition of NH3 is given as 29.9%, so we can set up the equation as follows:
29.9 = (n * 17.03) / (63.55 + (n * 17.03) + 96.06) * 100
5. Rearrange the equation to solve for "n":
n = (29.9 * (63.55 + 96.06)) / (17.03 * (100 - 29.9))
6. Calculate the value of "n" using the equation from step 5.
By following these steps, you can calculate the value of x (or n) in the coordination compound Cu(NH3)xSO4.