algebra

posted by .

I have been working this one for awhile and have become more confused. Please assist.
Problem:
Find two consecutive odd integers such that 5 times the first interger is 12 more than 3 times the second.

The key thing is to realize that odd numbers, just like the even numbers, are 2 apart
So if you let the first odd number be x, then the second odd number is x+2

Now all you do is translate the English into math.

"...such that 5 times the first interger is 12 more than 3 times the second."

5x > 3(x+2) by 12

so we add 12 to the smaller side to make it into an equation.

5x = 3(x+2) + 12

easy to solve

Similar Questions

1. Pre-Algebra

Find two consecutive odd integers such that 5 times the first integer is 12 more than 3 times the second. let X = 1st odd number. and Y = 2nd odd number = X + 2 since it is consecutive. Now set up two equations (the first is Y = X …
2. math

Determine whether there are 2 consecutive odd integers such that 5 times the first exceeds three times the second by 54. Can anyone help?
3. algebra

Find the two consecutive odd integers such that 5 times the first integer is 12 more than 3 times the second. can some explain to me how to get this i was thinking the formula would be ' 5x+12=3x No, that's not it. The second integer …
4. Algebra

Find two consecutive odd integers such that 5 times the first integer is 12 more than 3 times the second. I've gotten this far but confused as to what the two intergers are. 5x=3(x+2)=12 5x=3x+2+12 5x=3x+14 2x=14 2x/2x=14/2 x=7 Let …
5. Algebra II

Find 4 consecutive odd integers such that 5 times the sum of the first two was 10 less than 7 times the sum of the second and fourth. What are the four integers?
6. Algebra

Can you help me set this problem? it is as follows, "Find three consecutive odd integers such that their sum is 5 more than four times the larger."