algebra
posted by ken .
I have been working this one for awhile and have become more confused. Please assist.
Problem:
Find two consecutive odd integers such that 5 times the first interger is 12 more than 3 times the second.
The key thing is to realize that odd numbers, just like the even numbers, are 2 apart
So if you let the first odd number be x, then the second odd number is x+2
Now all you do is translate the English into math.
"...such that 5 times the first interger is 12 more than 3 times the second."
5x > 3(x+2) by 12
so we add 12 to the smaller side to make it into an equation.
5x = 3(x+2) + 12
easy to solve
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