Math,help
posted by jasmine20 .
how do i evalute this problem if possible.
i will decribe it
it has an index of 3 then a squaroot sign then for the radicand (64)
since the cube root of 64 is 4(4 times 4 times 4 = 64).. the () part, you just tack on, since a () times (+) times () equals a (). so the answer will be 4.
Check: 4 time 4 = 16.
16 times 4 = 64
Hope this helps....
Respond to this Question
Similar Questions

Inter. Algebra
Count Iblis how do you simplify 3square root sign with this underneath (3x squared y) to the third power? 
math
Can somebody please help me with this problem? 
Math
Hi i was wondering what the square root of 3 times the squareroot of 9 is with little 3's on on the outside of the square roots for each of them ( the index) sqrt3 *(sqrt9)= 3sqrt3 Is that little 3 a cube root sign? 
Math
i see were u got that from but this 1 is confusing. 6 (index 3) square root of 36 times 2 (index 3)square root of 6 Please use the following for roots: sqrt cubroot etc. Those, with parenthesis, make the problem clear. 6 cube root … 
Math
Im stumped by these: evaluate if possible: 3√64 (the 3 is supposed to be in the dip of the square root symbol) 4√81 ( the 3 is also supposed to be in the dip of the square root sign) 3√1/125 ( " " ) The cube root … 
Algebra
Could you please help me with some math problems? 
Algebra multiplying sq rt
I need to use rational exponents to write the answer to: the cube root of x times the 4 root of 7x. there is a rule when the numbers on the radicand are different, yes? 
Algebra
If 3 is the index, and there is no radicand, and inside of that radical is another radical with ten being the radicand, how could the result be 6 as the index with ten being the radicand? 
math
for what value of x (radicand) and n (index) can the expression "n root x " not be evaluated? 
Calculus 2
Determine whether the series is convergent, absolutely convergent, conditionally convergent, or divergent. On top of the summation sign (∑) is infinity. Under the summation sign is n=2, and right next to it (to the right of ∑ …