math,algebra
posted by jasmine20 .
Can someone set this up in equations so i can solve them i would greatly appreciate it. THanks.
Problem #3
The base of a ladder is 14 feet away from the wall. The top of the ladder is 17 feet from the floor. Find the length of the ladder to the nearest thousandth.
Problem #4
A rectangular garden is to be surrounded by a walkway of constant width. The garden's dimensions are 30 ft by 40 ft. The total area, garden plus walkway, is to be 1800 ft2. What must be the width of the walkway to the nearest thousandth?
112 because im smart im 10 and im in the 11th grade
oh sorry the answer is 2,000
the next one is 4,000
x+y=6
I do not want the answers just the equations.
3) Think about what shape that would make. If you're not sure, draw it out. The formula? a^2 + b^2 = .... ?
4) Again, this may help to draw out a picture of it. It would look like a rectangle inside of a rectangle. Now that you see that much, what's the area of the garden? We know it's 30ft x 40ft  which is 1200 ft^2
The area of the whole place is 1800 ft^2
So subtract 1800  1200 and we see the area of the walkway is 600 ft^2
Try to figure it out from there and see what you come up with.
Matt

EQUATION:
(30+2x)(40+2x) = 1800 sq ft.
4(15+x)(20+x) = 1800
x^2+35x+300=450
x^2+35x150=0
Use quadratic formula to get:
x=[35+sqrt(35^24*150)]/2
x=[35+sqrt1825]/2
x=[35+42.72]/2
x=7.72/2
x=3.86 ft 
Problem 4 solution:
EQUATION:
(30+2x)(40+2x) = 1800 sq ft.
4(15+x)(20+x) = 1800
x^2+35x+300=450
x^2+35x150=0
Use quadratic formula to get:
x=[35+sqrt(35^24*150)]/2
x=[35+sqrt1825]/2
x=[35+42.72]/2
x=7.72/2
x=3.86 ft
Respond to this Question
Similar Questions

math,help
can someone help me set this word problem up into equations so i can solve. I don't want the answer just if you could help me with how to set it up. thanks The base of ladder is 14feet away from the wall. The top of the ladder is 17feet … 
Math Calculus
A 20 foot ladder is sliding down a vertical wall at a constant rate of 2 feet per second. a) How fast is the ladder moving away from the wall when the base of the ladder is 12 feet away from the wall? 
Math Calculus
A 20 foot ladder is sliding down a vertical wall at a constant rate of 2 feet per second. a) How fast is the ladder moving away from the wall when the base of the ladder is 12 feet away from the wall? 
Math Calculus
A 20 foot ladder is sliding down a vertical wall at a constant rate of 2 feet per second. a) How fast is the ladder moving away from the wall when the base of the ladder is 12 feet away from the wall? 
Math Calculus
A 20 foot ladder is sliding down a vertical wall at a constant rate of 2 feet per second. a) How fast is the ladder moving away from the wall when the base of the ladder is 12 feet away from the wall? 
Calculus
a 5m ladder rests against a vertical wall. The top of the ladder begins sliding down the wall at 2m/sec, while the foot of the ladder moves away from the base of the wall. How fast is the foot of the ladder moving away from the wall … 
Complex Physics Problem
A ladder can fall for two reasons. If it is set too steep and climber gets their mass to the left of the ladder's base, the ladder likely will fall over backwards. If the ladder is set at too shallow of an angle the required force … 
Calculus
A 17 foot ladder is leaning against a wall. The bottom of the ladder is moving out away from the wall at 0.6 feet per second. The top of the ladder then begins sliding down the wall. How fast is the top of the ladder going when the … 
algebra
Sheila is climbing on a ladder that is attached against the side of a jungle gym wall. She is 5 feet off the ground and 3 feet from the base of the ladder, which is 15 feet from the wall. How high up the wall is the top of the ladder? 
Calculus
A ladder 25 feet long is leaning against the wall of a house. The base of the ladder is pulled away from the wall at a rate of 2 feet per second. How fast is the top of the ladder moving down the wall when its base is 7 feet?