Calculus
posted by Evan .
Find derivative: (write answer as single fraction)
y=ln((4x1)/x^3)
So far I have:
y'=(4/(4x1))3/x
How do I write as single fraction
let u= (4x1) v= x^3
dy/dx= d y/d(uv) * d(uv)/dx
dy/duv= 1/uv
d(uv)/dx= udv/dx + v du/dx
put it together.
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