# Calculus

posted by
**Evan**
.

Find derivative: (write answer as single fraction)

y=ln((4x-1)/x^3)

So far I have:

y'=(4/(4x-1))-3/x

How do I write as single fraction

let u= (4x-1) v= x^-3

dy/dx= d y/d(uv) * d(uv)/dx

dy/duv= 1/uv

d(uv)/dx= udv/dx + v du/dx

put it together.