posted by .

Find the derivative:


i have so far 2(2x)e^(x^2+1)^3

Is this correct? How do I simplify furthere if it is?


d/dx (f(x))= d/du(f(u)) du/dx

let u= (x^2+1)^3

y= 2e^u

dy/du= 2e^u

du/dx= 3*(x^2+1)^2 * 2x

dy/dx= dy/du *( du/dx)

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Calculus (Help)

    Also I would like to know how to set this problem up in finding the answer: Find the second derivative. y= sqrt(3x+4) Thanks, P.S. I tried taking 3x+4 and squaring it to the 1/2. I thought that might've been the same, then I took the …
  2. calc

    derivative of (x^3/6)+(1/2x)? i got (x^2/2)-(1/2x^2) is that correct?
  3. Calculus--> bobpursley

    How do you get m=0? from taking the second derivative?
  4. Calculus - derivatives

    Okay, I want to find the derivative of (x^x)^(x^x)... Well, I already went through the process of finding the derivative of just x^x (I used ln to do this). This is what I found... dy/dx = x^x(lnx+1) So now I want to find the derivative …
  5. Calculus

    If P'(t)= [10(t+2)]/t. What is P(t)? It is asking for the derivative, and I am so lost! Because so far we haven't covered how to find the derivative of something so complicated. Any ideas?
  6. Calculus

    Find the derivative of f(x)=x(1-4^x) f'(x)=(1-4^x)+ (-4^x)(ln-4)(-4)(x) ln can't be negative. Is the derivative correct?
  7. calculus

    Find the first and second derivative - simplify your answer. y=x/4x+1 I solved the first derivative and got 1/(4x+1)^2 Not sure if I did the first derivative right and not sure how to do the second derivative.
  8. Calculus 1

    Find the derivative dy/dx for the following. Simplify your answer. y=(ln(x^2))/(x^3) I got (2/x x^3-3x^2 ln(x^2))/((x^3)^2) for the derivative is that correct?
  9. Calculus,Stationary Points,First derivative test

    Good afternoon, I need a bit of help. So ive got my first derivative which is 6x^2-6x-12 and the stationary points ive found are x=-1 and x=2 at which points the value of the derivative is zero. So im attempting to classify the points. …
  10. calculus

    One litre of water at 0 degrees Celsius will have a different volume at higher temperatures. For a temperature 0 ≤ T ≤ 30 (in Celsius) this volume (in litres) is well approximated by the function V = −aT 3 + bT 2 − cT + 1 using …

More Similar Questions