ALGEBRA 1

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CAN SOMEONE PLEASE CHECK TO SEE IF I HAVE DONE THESE CORRECTLY. Thanks for your help.

Solve by completing the square
1. X^2-6x=16
X^2-6x + (-6/2) ^2=16+ (-6/2) ^2
X^2-6x+36/4= 16+36/4
(X-6/2)=100/4
X-6/2= +or - 10/2
X=6 + or - 10/2
X=-4, X=8


2. 2x^2-3x+1
2x^2-3x=-1
X^2-3/2x=-1/2
X^2-3/2x +(-3/2)^2 =-1/2+(-3/2)^2
X^2-3/2+9/4 =-1/2+9/4
X+3/2=7/4
X+3/2=+ or - sqrt7/4
X=-3 + or – sqrt 7/2
X= -3+sqrt7/2 , x=-3-sqrt7/2



Put the values in the letters and see if you get the right answer

For example

Put the value for your first answer as

-4 squared - 6(8) = 16

See if it works in this way

No1 in line 4
why don't your reduce 6/2 to 3
line 4 would read (x-3)^2 = 25
then x-3 = +/- √25
x-3 = +/- 5
then x=8 or x = -2

no 2 you have to take 1/2 of 3/2 which would be 3/4.
then 3/4 squared is 9/16

so line 4 should read

x^2 - (3/2)x + 9/16 = -1/2 + 9/16
.
.
.
(x-3/4)^2 = 1/16
..

x=1 or x=1/2

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