Vectors Help me pls!
posted by Segun .
Dtermine the value of a so that
u=2i+aj+k and 4i2j2k are perpendicular
Did you just start this topic?
This is a very easy question.
if two vectors are perpendicular, then their dot product must be zero
then (2,a,1).(4,2,2)=0
82a2=0
a=3
Respond to this Question
Similar Questions

Vectors
Given vectors A = 4.8i + 6.8j and B = 9.6i + 6.7j, determine the vector C that lies in the xy plane perpendicular to B and whose dot product with A is 20.0. 
math
two vectors are defined as a=2i+xj and b=i4j. find value of x if a) the vectors are parallel b) the vectors are perpendicular 
math
two vectors are defined as a=2i+xj and b=i4j. find value of x if a) the vectors are parallel b) the vectors are perpendicular 
Physics
2. We have two vectors that line in the xy plane. If we take the crossproduct of those two vectors we know that a. the magnitude of the crossproduct will always be equal to the product of the magnitudes of the two vectors. b. the … 
Calculus III Please Help
2. Use the properties of the dot product to show that (⃗b·⃗c)a−(⃗a·⃗c)⃗b is perpendicular to ⃗c. Must be shown for arbitrary vectors. I have tried to assign each vector (b,a,c) arbitrary … 
Vector Calculus
2. Use the properties of the dot product to show that (⃗b·⃗c)a−(⃗a·⃗c)⃗b is perpendicular to ⃗c. Must be shown for arbitrary vectors. Im sorry, I'm really stuck on this. I know that is a … 
Calculus
Two force vectors act on an object and the dot product of the two vectors is 20. If both of the force vectors are doubled in magnitude, what is their new dot product? 
math
given that vectors(p+2q) and (5p4q) are orthogonal,if vectors p and q are the unit vectors,find the dot product of vectors p and q? 
Calculus and Vectors
THE VECTORS a  5b AND ab ARE PERPENDICULAR. IF a AND b ARE UNIT VECTORS, THEN DETERMINE a dot b 
perpendicular vectors
Find two unit vectors each of which is perpendicular to vectors (1, 1, 0) and (1,0,1) What I did: a x b = (1, 1, 1) axb=square toot 3 correct answer is +/ (1/√3  1/√3  1/√3) or =+/ 1/√3 (1, 1, 1)