x = (-5 +/-�ã85)/10
do you mean -0.5 or -5
is this right?
solve by using the quadratic formula:
5x^2+5x=3
i get:
x= -0.5 (+/-)((sqrt(85)/(5))
check up on your proper use of the formula
I got x = (-5 +/-√85)/10
which, if you want to separate it into two terms is
1/2 +/- √85/10 (you had /5)
some of your teachers might consider it "bad form" to give an answer partially in decimals and partially in fractions
Choose either one or the other.
To solve the quadratic equation 5x^2 + 5x = 3 using the quadratic formula, we start by identifying the values of a, b, and c in the general quadratic equation form ax^2 + bx + c = 0.
In this case, a = 5, b = 5, and c = -3. We can then substitute these values into the quadratic formula:
x = (-b +/- sqrt(b^2 - 4ac)) / (2a)
Substituting the values, we have:
x = (-5 +/- sqrt(5^2 - 4(5)(-3))) / (2(5))
x = (-5 +/- sqrt(25 + 60)) / 10
x = (-5 +/- sqrt(85)) / 10
Therefore, the solutions to the equation are (-5 +/- sqrt(85)) / 10.
Thus, your answer of x = (-0.5 +/- ((sqrt(85))/(5)) is incorrect. The correct form is x = (-5 +/- sqrt(85))/10.
Regarding your choice of presenting the answer as a mixture of decimals and fractions, it is best to choose either one or the other for consistency. In this case, presenting the answer as decimals would yield x = -0.5 +/- 0.2955 (rounded to four decimal places).